Answer
$=-\frac{(3x-4)}{(x-4)} $
Work Step by Step
$\frac{(x-8)}{(x-4)} \times \frac{(3x-4)}{(8-x)}$
$= \frac{(x-8)(3x-4)}{(x-4)(8-x)} $
$=\frac{(x-8)(3x-4)}{(x-4)(-(x-8))} $
$=\frac{(3x-4)}{-(x-4)} $
$=-\frac{(3x-4)}{(x-4)} $
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