Answer
$= -\frac{(2x+3)}{(x+3)}$
Work Step by Step
$\frac{(7-x)}{(x+3)} \times \frac{(2x+3)}{(x-7)}$
$= \frac{(7-x)(2x+3)}{(x+3)(x-7)}$
$= \frac{(-(x-7))(2x+3)}{(x+3)(x-7)}$
$= \frac{-(2x+3)}{(x+3)}$
$= -\frac{(2x+3)}{(x+3)}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 580: 7
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