## Intermediate Algebra: Connecting Concepts through Application

Shania forgot to multiply by the reciprocal fraction when dividing. Once this step is done, she can start cancelling out the factors to find the answer. $= \frac{(h+5)(h+4)^{2}}{(h+7)(h+2)^{2}}$
Shania forgot to multiply by the reciprocal fraction when dividing. Once this step is done, she can start cancelling out the factors to find the answer. $\frac{(h+4)(h-8)}{(h+2)(h+7)} \div \frac{(h-8)(h+2)}{(h+4)(h+5)}$ $= \frac{(h+4)(h-8)}{(h+2)(h+7)} \times \frac{(h+4)(h+5)}{(h-8)(h+2)}$ $= \frac{(h+4)}{(h+2)(h+7)} \times \frac{(h+4)(h+5)}{(h+2)}$ $= \frac{(h+4)(h+4)(h+5)}{(h+2)(h+7)(h+2)}$ $= \frac{(h+5)(h+4)^{2}}{(h+7)(h+2)^{2}}$