## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 580: 22

#### Answer

Shania forgot to multiply by the reciprocal fraction when dividing. Once this step is done, she can start cancelling out the factors to find the answer. $= \frac{(h+5)(h+4)^{2}}{(h+7)(h+2)^{2}}$

#### Work Step by Step

Shania forgot to multiply by the reciprocal fraction when dividing. Once this step is done, she can start cancelling out the factors to find the answer. $\frac{(h+4)(h-8)}{(h+2)(h+7)} \div \frac{(h-8)(h+2)}{(h+4)(h+5)}$ $= \frac{(h+4)(h-8)}{(h+2)(h+7)} \times \frac{(h+4)(h+5)}{(h-8)(h+2)}$ $= \frac{(h+4)}{(h+2)(h+7)} \times \frac{(h+4)(h+5)}{(h+2)}$ $= \frac{(h+4)(h+4)(h+5)}{(h+2)(h+7)(h+2)}$ $= \frac{(h+5)(h+4)^{2}}{(h+7)(h+2)^{2}}$

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