#### Answer

$= xy^{2}$

#### Work Step by Step

$\frac{15x^{2}}{9y^{3}} \times \frac{21y^{5}}{35x}$
$= \frac{15x^{2}}{9y^{3}} \times \frac{21y^{5}}{35x}$
$= \frac{15x^{2}(21y^{5})}{9y^{3}(35x)}$
$= \frac{315x^{2}y^{5}}{315y^{3}x}$
$= \frac{x^{2}y^{5}}{xy^{3}}$
$= \frac{xy^{5}}{y^{3}}$
$= \frac{xy^{2}}{1}$
$= xy^{2}$