Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 97

Answer

$-8\sqrt{5}$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, the expression $ (\sqrt{5}-5)(2\sqrt{5}+2) $ simplifies to \begin{array}{l} (\sqrt{5})(2\sqrt{5})+(\sqrt{5})(2)-5(2\sqrt{5})-5(2) \\= 2\sqrt{25}+2\sqrt{5}-10\sqrt{5}-10 \\= 2\cdot5-8\sqrt{5}-10 \\= 10-8\sqrt{5}-10 \\= -8\sqrt{5} .\end{array}
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