Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 88

Answer

$2x\sqrt{3x}$

Work Step by Step

Using the properties of radicals, the expression $ x\sqrt{75x}-\sqrt{27x^3} $ simplifies to \begin{array}{l} x\sqrt{25\cdot3x}-\sqrt{9x^2\cdot3x} \\= x\cdot5\sqrt{3x}-3x\sqrt{3x} \\= 5x\sqrt{3x}-3x\sqrt{3x} \\= 2x\sqrt{3x} .\end{array}
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