## Intermediate Algebra (6th Edition)

$\dfrac{11}{3\sqrt[]{11}}$
Multiplying both the numerator and the denominator by a factor that will make the numerator a perfect power of the radical, the rationalized-numerator form of the given expression, $\dfrac{\sqrt[]{11}}{3} ,$ is \begin{array}{l}\require{cancel} \dfrac{\sqrt[]{11}}{3}\cdot\dfrac{\sqrt[]{11}}{\sqrt[]{11}} \\\\= \dfrac{\sqrt[]{(11)^2}}{3\sqrt[]{11}} \\\\= \dfrac{11}{3\sqrt[]{11}} .\end{array}