Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 102

Answer

$a+64$

Work Step by Step

Using $(a+b)(a^2-ab+b^2)=a^3+b^3$, the expression $ (\sqrt[3]{a}+4)(\sqrt[3]{a^2}-4\sqrt[3]{a}+16) $ simplifies to \begin{array}{l} (\sqrt[3]{a})^3+(4)^3 \\= a+64 .\end{array}
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