## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Review: 61

2x

#### Work Step by Step

$\frac{\sqrt (44x^{3})}{\sqrt (11x)}=\sqrt \frac{(44x^{3})}{(11x)}=\sqrt (4x^{2})=\sqrt 4\times\sqrt (x^{2})=2x$ We know that $\sqrt 4=2$, because $2^{2}=4$. We also know that $\sqrt (x^{2})=x$, because $(x)^{2}=x^{2}$.

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