Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 58

Answer

$\sqrt[12] (81x^{3})$

Work Step by Step

$\sqrt[3] 3\times\sqrt[4] x=3^{\frac{1}{3}}\times x^{\frac{1}{4}}=3^{\frac{4}{12}}\times x^{\frac{3}{12}}=(3^{4}\times x^{3})^{\frac{1}{12}}=(81x^{3})^{\frac{1}{12}}=\sqrt[12] (81x^{3})$
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