Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 56



Work Step by Step

$105^{-\frac{2}{3}}=\frac{1}{105^{\frac{2}{3}}}=\frac{1}{\sqrt[3] (105^{2})}=.045$ In this case, we are finding the reciprocal of $\sqrt[3] (105^{2})=22.257$. $\frac{1}{22.257}=.045$
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