Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 73


$\frac{5}{\sqrt \pi}$ meters

Work Step by Step

We are given that the radius of a circle of area A is given by the function $r=\sqrt (\frac{A}{\pi})$. Furthermore, we are given that the area of the circle is 25 square meters. Therefore, $r=\sqrt (\frac{25}{\pi})=\frac{\sqrt 25}{\sqrt \pi}=\frac{5}{\sqrt \pi}$ meters. We know that $\sqrt 25=5$, because $5^{2}=25$.
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