Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 57


$\sqrt[6] 1372$

Work Step by Step

$\sqrt[3] 2\times\sqrt 7=2^{\frac{1}{3}}\times7^{\frac{1}{2}}=2^{\frac{2}{6}}\times7^{\frac{3}{6}}=(2^{2}\times7^{3})^{\frac{1}{6}}=(4\times343)^{\frac{1}{6}}=1372^{\frac{1}{6}}=\sqrt[6] 1372$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.