Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 89

Answer

$9\sqrt[3]{2}$

Work Step by Step

Using the properties of radicals, the expression $ \sqrt[3]{128}+\sqrt[3]{250} $ simplifies to \begin{array}{l} \sqrt[3]{64\cdot2}+\sqrt[3]{125\cdot2} \\= 4\sqrt[3]{2}+5\sqrt[3]{2} \\= 9\sqrt[3]{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.