Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 67


$6x^{3}\sqrt x$

Work Step by Step

$\sqrt (36x^{7})=\sqrt (36\times x^{6}\times x)=\sqrt 36\times\sqrt (x^{6})\times\sqrt x=6x^{3}\sqrt x$ We know that $\sqrt 36=6$, because $6^{2}=36$. We also know that $\sqrt (x^{6})=x^{3}$, because $(x^{3})^{2}=x^{3\times2}=x^{6}$
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