Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 469: 70



Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt[3]{\dfrac{y^5}{27x^6}} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{\dfrac{y^3}{27x^6}\cdot y^2} \\\\= \sqrt[3]{\left( \dfrac{y}{3x^2} \right)^3\cdot y^2} \\\\= \dfrac{y}{3x^2}\sqrt[3]{y^2} \\\\= \dfrac{y\sqrt[3]{y^2}}{3x^2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.