Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 45

Answer

x=0.5 y=0.2 (0.5,0.2)

Work Step by Step

$10y-2x=1$ $5y=4-6x$ Solve for y in the second equation. $5y=4-6x\longrightarrow$ Multiply both sides by $\frac{1}{5}$. $\frac{1}{5}(5y)=\frac{1}{5}(4-6x)\longrightarrow$ Simplify. Apply the distributive property. $y=\frac{4}{5}-\frac{6}{5}x$ Substitute for y in the first equation. $10(\frac{4}{5}-\frac{6}{5}x)-2x=1\longrightarrow$ Simplify. Apply the distributive proeprty. $\frac{40}{5}-\frac{60}{5}x-2x=1\longrightarrow$ Simplify. $8-12x-2x=1\longrightarrow$ Simplify. $8-14x=1\longrightarrow$ Subtract 8 from both sides.. $8-14x-8=1-8\longrightarrow$ Simplify. $-14x=-7\longrightarrow$ Divide both sides by -14. $-14x\div-14=-7\div-14\longrightarrow$ Simplify. $x=0.5$ Substitute for x and solve for y. $10y-2(0.5)=1\longrightarrow$ Simplify. $10y-1=1\longrightarrow$ Add 1 to both sides. $10y-1+1=1+1\longrightarrow$ Simplify. $10y=2\longrightarrow$ Divide both sides by 10. $10y\div10=2\div10\longrightarrow$ Simplify. $y=0.2$
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