Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 22

Answer

x=0 y=-2 (0,-2)

Work Step by Step

$\frac{x}{8}-\frac{y}{2}=1$ $\frac{x}{3}-y=2$ Use substitution to solve for x and y. Isolate x on one side of the equation. $\frac{x}{8}-\frac{y}{2}=1\longrightarrow$ Mutiply both sides by 8 to eliminate fractions. $8(\frac{x}{8}-\frac{y}{2})=8(1)\longrightarrow$ Apply the distributive property. $\frac{8x}{8}-\frac{8y}{2}=8\longrightarrow$ Simplify. $x-4y=8\longrightarrow$ Add 4y to both sides. $x-4y+4y=8+4y\longrightarrow$ Simplify. $x=8+4y$ Substitute for x in the second equation and solve for y. $\frac{8+4y}{3}-y=2\longrightarrow$ Multiply both sides by 3. $3(\frac{8+4y}{3}-y)=3(2)\longrightarrow$ Apply the distributive property. $3(\frac{8+4y}{3})-3y=6\longrightarrow$ Simplify. $8+4y-3y=6\longrightarrow$ Simplify. $8+y=6\longrightarrow$ Subtract 8 from both sides. $8+y-8=6-8$ Simplify. $y=-2$ Substitute for y and solve for x. $\frac{x}{3}-(-2)=2\longrightarrow$ Simplify. $\frac{x}{3}+2=2\longrightarrow$ Subtract 2 from both sides. $\frac{x}{3}+2-2=2-2\longrightarrow$ Simplify. $\frac{x}{3}=0\longrightarrow$ Multiply both sides by 3. $\frac{x}{3}\times3=0\times3\longrightarrow$ Simplify. $x=0$
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