Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 21

Answer

x=-5 y=3 (-5,3)

Work Step by Step

$\frac{x}{3}+y=\frac{4}{3}$ $-x+2y=11$ Use substitution to solve. Isolate one variable in one equation. $\frac{x}{3}+y=\frac{4}{3}\longrightarrow$ Subtract $\frac{x}{3}$ from both sides. $\frac{x}{3}+y-\frac{x}{3}=\frac{4}{3}-\frac{x}{3}\longrightarrow$ Simplify $y=\frac{4}{3}-\frac{x}{3}$ Substitute for y in the other equation and solve for x. $-x+2(\frac{4}{3}-\frac{x}{3})=11\longrightarrow$ Apply the distributive property. $-x+\frac{8}{3}-\frac{2x}{3}=11\longrightarrow$ Multiply both sides by 3. $3(-x+\frac{8}{3}-\frac{2x}{3})=3(11)\longrightarrow$ Apply the distributive property. $-3x+8-2x=33\longrightarrow$ Combine like terms. $-5x+8=33\longrightarrow$ Subtract 8 from both sides. $-5x+8-8=33-8\longrightarrow$ Simplify. $-5x=25\longrightarrow$ Divide both sides by -5. $-5x\div-5=25\div-5\longrightarrow$ Simplify. $x=-5$ Substitute for x in one equation and solve for y. $-(-5)+2y=11\longrightarrow$ Simplify. $5+2y=11\longrightarrow$ Subtract 5 from both sides. $5+2y-5=11-5\longrightarrow$ Simplify. $2y=6\longrightarrow$ Divide both sides by 2. $2y\div2=6\div2\longrightarrow$ Simplify. $y=3$
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