Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 18

Answer

x=2 y=0 (2,0)

Work Step by Step

$3x-y=6$ $-4x+2y=-8$ Solve the system of equations using substitution. Isolate one variable on one side of one equation. $3x-y=6\longrightarrow$ Add y to both sides of the equation. $3x-y+y=6+y\longrightarrow$ Simplify. $3x=6+y\longrightarrow$ Subtract 6 from both sides. $3x-6=6+y-6\longrightarrow$ Simplify $3x-6=y$ Substitute for y in the second equation. Solve for x. $-4x+2(3x-6)=-8\longrightarrow$ Apply the distributive property. $-4x+6x-12=-8\longrightarrow$ Simplify. $2x-12=-8\longrightarrow$ Add 12 to both sides. $2x-12+12=-8+12\longrightarrow$ Simplify. $2x=4\longrightarrow$ Divide both sides by 2. $2x\div2=4\div2\longrightarrow$ Divide both sides by 2. $x=2$ Substitute for x in either equation and solve for y. $3(2)-y=6\longrightarrow$ Simplify $6-y=6\longrightarrow$ Subtract 6 from both sides. $6-y-6=6-6\longrightarrow$ Simplify. $-y=0\longrightarrow$ Divide both sides by -1. $-y\div-1=0\div-1\longrightarrow$ Simplify. $y=0$
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