Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 43

Answer

This system has no solution.

Work Step by Step

$4x+2y=5$ $2x+y=-1$ Solve for in the second equation. $2x+y=-1\longrightarrow$ Subtract 2x from both sides. $2x+y-2x=-1-2x\longrightarrow$ Simplify. $y=-1-2x$ Substitute for y in the first equation. $4x+2(1-2x)=5\longrightarrow$ Simplify. Apply the distributive property. $4x+2-4x=5\longrightarrow$ Simplify. $2=5$ Since the substitution results in a false statement, there is no solution for this system of equations.
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