Answer
$x=\frac{1}{2}$
$y=\frac{1}{3}$
$(\frac{1}{2},\frac{1}{3})$
Work Step by Step
$-2x+3y=0$
$2x+6y=3$
Add the two equations together to eliminate x.
$-2x+3y=0$
$\underline{\ \ \ 2x+6y=3}$
$\ \ \ \ \ \ \ \ \ \ \ \ 9y=3$
Solve for y.
$9y=3\longrightarrow$ Divide both sides by 9.
$9y\div9=3\div9\longrightarrow$ Simplify and reduce.
$y=\frac{3}{9}=\frac{1}{3}$
Substitute for y and solve for x.
$-2x+3(\frac{1}{3})=0\longrightarrow$ Simplify.
$-2x+1=0\longrightarrow$ Add 2x to both sides.
$-2x+1+2x=0+2x\longrightarrow$ Simplify.
$1=2x\longrightarrow$ Divide both sides by 2.
$1\div2=2x\div2\longrightarrow$ Simplify.
$\frac{1}{2}=x$
