Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 36

Answer

Ordered pair solution : $(-2,\frac{3}{4})$

Work Step by Step

(1) $x-4y=-5 $ (2) $-3x-8y=0 $ To eliminate $x$ multiply (1) by $3$ (3) $3x -12y = -15 $ Add (2) and (3) $-3x +3x -8y-12y = 0-15$ $-20 y = -15$ $y = \frac{-15}{-20}$ $y = \frac{3}{4}$ Substitute $y$ value in Equation (1) $x-4(\frac{3}{4})=-5 $ $x -3 = -5$ $x = -5+3 $ $x =-2$ Ordered pair solution : $(-2,\frac{3}{4})$
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