Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 26

Answer

x=-2 y=-7 (-2,-7)

Work Step by Step

$6x-y=-5$ $4x-2y=6$ Equate the coefficients of y to eliminate y and solve for x. $6x-y=-5\longrightarrow$ Multiply both sides by 2. $2(6x-y)=2(-5)\longrightarrow$ Apply the distributive property. $12x-2y=-10$ Subtract the second equation from the new equation. $\ \ \ 12x-2y=-10$ $\underline{-(4x-2y=6)}$ $\ \ \ 8x\ \ \ \ \ \ \ \ \ \ \ =-16$ Solve for x. $8x=-16\longrightarrow$ Divide both sides by 8. $8x\div8=-16\div8\longrightarrow$ Simplify. $x=-2$ Substitute for x and solve for y. $6(-2)-y=-5\longrightarrow$ Simplify. $-12-y=-5\longrightarrow$ Add 12 to both sides. $-12-y+12=-5+12\longrightarrow$ Simplify. $-y=7\longrightarrow$ Multiply both sides by -1. $-y\times-1=7\times-1\longrightarrow$ Simplify. $y=-7$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.