Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 35

Answer

Ordered Pair Solution $(\frac{3}{2},1)$

Work Step by Step

We have $$(1)2x+5y = 8$$ $$(2)6x+y=10$$ (1) - 5(2) $$2x -30x +5y -5y = 8 -50$$ $$-28x = -42$$ $$x= \frac{3}{2}$$ Solving for $y$ $$y = 10 - 6(\frac{3}{2}) = 1$$ Ordered Pair Solution $(\frac{3}{2},1)$
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