Answer
Ordered pair solution $(1,-1)$
Work Step by Step
We have $$(1) \frac{1}{2}x+\frac{3}{4}y=-\frac{1}{4}$$ $$(2)\frac{3}{4}x-\frac{1}{4}y=1$$
From (1) $$(3)y = (-\frac{1}{2}x-\frac{1}{4})*\frac{4}{3} = -\frac{2}{3}x-\frac{1}{3} $$
Substituting (3) in (2) $$\frac{3}{4}x-\frac{1}{4}(-\frac{2}{3}x-\frac{1}{3}) = 1$$ $$\frac{3}{4}x+\frac{1}{6}x+\frac{1}{12} = 1$$ $$\frac{11}{12}x=\frac{11}{12}$$ $$x=1$$
Solving for $y$ $$y = -\frac{2}{3}(1)-\frac{1}{3} = -1$$
Ordered pair solution $(1,-1)$
