Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 33

Answer

{(x,y)|3x+y=1}

Work Step by Step

$3x+y=1$ $2y=2-6x$ Use substitution to solve for x and y. Isolate y in the first equation. $3x+y=1\longrightarrow$ Subtract 3x from both sides. $3x+y-3x=1-3x\longrightarrow$ Simplify. $y=1-3x$ Substitute for y in the second equation. $2(1-3x)=2-6x\longrightarrow$ Apply the distributive property. $2-6x=2-6x$ Since the above statement is always true, the solution set for (x,y) contains every pair of values that satisfy either of the equations.
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