Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 23

Answer

x=2.5 y=1.25 (2.5,1.25)

Work Step by Step

$-x+2y=0$ $x+2y=5$ Substitute to solve for x and y. Isolate x on one side of one of the equations. $x+2y=5\longrightarrow$ Subtract 2y from both sides. $x+2y-2y=5-2y\longrightarrow$ Simplify. $x+5-2y$ Substitute for x in the other equation then solve for y. $-(5-2y)+2y=0\longrightarrow$ Apply the distributive property. $-5+2y+2y=0\longrightarrow$ Simplify. $-5+4y=0\longrightarrow$ Add 5 to both sides. $-5+4y+5=0+5\longrightarrow$ Simplify. $4y=5\longrightarrow$ Divide both sides by 4. $4y\div4=5\div4\longrightarrow$ Simplify. $y=1.25$ Substitute for y and solve for x. $x+2(1.25)=5\longrightarrow$ Simplify. $x+2.5=5\longrightarrow$ Subtract 2.5 from both sides. $x+2.5-2.5=5-2.5\longrightarrow$ Simplify. $x=2.5$
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