Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Review Exercises - Page 637: 19

Answer

$2.5850$

Work Step by Step

Using $\log_bx=\dfrac{\log x}{\log b}$ or the Change-of-Base Formula, the given expression, $ \log_2 6 ,$ is equivalent to \begin{align*} & \dfrac{\log6}{\log2} .\end{align*} Using a calculator, with $ \log6\approx0.77815 $ and $ \log2\approx0.30103 $, then \begin{align*} \dfrac{\log6}{\log2}&\approx \dfrac{0.77815}{0.30103} \\\\&\approx 2.5850 .\end{align*} Hence, the approximate value of $ \log_2 6 $, is $ 2.5850 $.
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