Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Review Exercises - Page 637: 15

Answer

$5^{2x+1}=25$

Work Step by Step

Expressing both sides of the given equation, $ 5^{2x+1}=25 ,$ in the same base, the equation above is equivalent to \begin{align*} 5^{2x+1}=5^2 .\end{align*} Since $a^x=a^y$ implies $x=y$, the equation above implies \begin{align*} 2x+1&=2 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} 2x+1-1&=2-1 \\ 2x&=1 \\\\ \dfrac{\cancel2x}{\cancel2}&=\dfrac{1}{2} \\\\ x&=\dfrac{1}{2} .\end{align*} Hence, the solution to the equation $ 5^{2x+1}=25 $ is $x=\dfrac{1}{2}$.
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