Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Review Exercises - Page 637: 25

Answer

$\left\{2\right\}$

Work Step by Step

Using the properties of logarithms, the given equation, $ \log_8 64=x $, is equivalent to \begin{align*} \log_8 8^2&=x \\ 2\log_8 8&=x &(\text{use }\log_b x^y=y\log_b x) \\ 2(1)&=x &(\text{use }\log_b b=1) \\ 2&=x .\end{align*} Hence, the solution set of the equation $ \log_8 64=x $ is $ \left\{2\right\} $.
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