Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Review Exercises - Page 637: 31

Answer

$\$300,000$

Work Step by Step

Using the given formula, $ S(x)=100\log_2(x+2) $, with $x=6$, then \begin{align*}\require{cancel} S(6)&=100\log_2(6+2) \\ &=100\log_28 \\ &=100\log_2 2^3 \\ &=100\cdot3\log_2 2 &(\text{use }\log_b x^y=y\log_b x) \\ &=100\cdot3(1) &(\text{use }\log_b b=1) \\ &=300 .\end{align*} Hence, the total sales after $6$ weeks, $S(6)$, of introducing a major advertising campaign is $\$300,000$.
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