Answer
$\dfrac{y^{9}}{8}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{2^2y^4(y^{-3})^{-1}}{2^5y^{-2}}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{2^2y^4(y^{-3(-1)})}{2^5y^{-2}}
\\\\=
\dfrac{2^2y^4y^{3}}{2^5y^{-2}}
\\\\=
2^{2-5}y^{4+3-(-2)}
\\\\=
2^{-3}y^{4+3+2}
\\\\=
\dfrac{y^{9}}{2^3}
\\\\=
\dfrac{y^{9}}{8}
.\end{array}