Answer
$\dfrac{4}{a^2}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{4a^5(a^{-1})^3}{(a^{-2})^{-2}}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{4a^5(a^{-1(3)})}{(a^{-2(-2)})}
\\\\=
\dfrac{4a^5(a^{-3})}{a^{4}}
\\\\=
\dfrac{4a^{5+(-3)}}{a^{4}}
\\\\=
\dfrac{4a^{2}}{a^{4}}
\\\\=
4a^{2-4}
\\\\=
4a^{-2}
\\\\=
\dfrac{4}{a^2}
.\end{array}