Answer
$\dfrac{9}{p^{11}}$
Work Step by Step
Using the laws of exponents, the given expression, $
(3p^{-4})^2(p^3)^{-1}
,$ is equivalent to
\begin{array}{l}\require{cancel}
3^2p^{-4(2)}(p^{3(-1)})
\\\\=
9p^{-8}(p^{-3})
\\\\=
9p^{-8+(-3)}
\\\\=
9p^{-8-3}
\\\\=
9p^{-11}
\\\\=
\dfrac{9}{p^{11}}
.\end{array}