Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 127

Answer

$\dfrac{1}{2pq}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{(3pq)q^2}{6p^2q^4} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{3}pq^{1+2}}{\cancel{3}(2)p^2q^4} \\\\= \dfrac{pq^{3}}{2p^2q^4} \\\\= \dfrac{p^{1-2}q^{3-4}}{2} \\\\= \dfrac{p^{-1}q^{-1}}{2} \\\\= \dfrac{1}{2p^1q^1} \\\\= \dfrac{1}{2pq} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.