Answer
$\frac{32}{x^{5}}$
Work Step by Step
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $(\frac{x}{2})^{-5}=\frac{1}{(\frac{x}{2})^{5}}=(\frac{2}{x})^{5}=\frac{2^{5}}{x^{5}}=\frac{32}{x^{5}}$.