Answer
$\frac{1}{16}$
Work Step by Step
According to the product rule for exponents, $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are integers and $a$ is a real number).
Therefore, $4^{4}\times 4^{-6}=4^{4+(-6)}=4^{-2}$.
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $4^{-2}=\frac{1}{4^{2}}=\frac{1}{16}$.