Answer
$\frac{25}{16}$
Work Step by Step
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $(\frac{4}{5})^{-2}=\frac{1}{(\frac{4}{5})^{2}}=\frac{5^{2}}{4^{2}}=\frac{25}{16}$.
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