Answer
$\frac{27}{8}$
Work Step by Step
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $(\frac{2}{3})^{-3}=\frac{1}{(\frac{2}{3})^{3}}=\frac{3^{3}}{2^{3}}=\frac{27}{8}$.
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