Answer
$-2m^{5}$
Work Step by Step
According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number).
Therefore, $-2m^{-1}(m^{3})^{2}=-2m^{-1}m^{3\times2}=-2m^{-1}m^{6}$.
According to the product rule for exponents, $a^{m}\times a^{n}=a^{m+n}$.
Therefore, $-2m^{-1}m^{6}=-2m^{-1+6}=-2m^{5}$.
