# Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 130

$2k^{5}$

#### Work Step by Step

Using the laws of exponents, the given expression, $\dfrac{12k^{-2}(k^{-3})^{-4}}{6k^5} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{6}(2)k^{-2}(k^{-3(-4)})}{\cancel{6}k^5} \\\\= \dfrac{2k^{-2}(k^{12})}{k^5} \\\\= 2k^{-2+12-5} \\\\= 2k^{5} .\end{array}

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