Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 278: 122



Work Step by Step

Using the laws of exponents, the given expression, $ 3a^2(-5a^{-6})(-2a)^0 ,$ is equivalent to \begin{array}{l}\require{cancel} 3a^2(-5a^{-6})(1) \\\\= -15a^{2+(-6)} \\\\= -15a^{2-6} \\\\= -15a^{-4} \\\\= -\dfrac{15}{a^4} .\end{array}
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