## Elementary Algebra

{$\frac{1}{2},8$}
We equate both the factors to zero and solve: $(2x-1)(x-8)=0$ $(2x-1)=0$ and $(x-8)=0$ $2x=1$ and $x=8$ $x=\frac{1}{2}$ and $x=8$ Therefore, the solution set is {$\frac{1}{2},8$}.