Answer
$\frac{12}{7}$
Work Step by Step
First, we simplify the expression within the parenthesis:
$(\frac{1}{3}+\frac{1}{4})^{-1}$
=$(\frac{1(4)+1(3)}{12})^{-1}$
=$(\frac{4+3}{12})^{-1}$
=$(\frac{7}{12})^{-1}$
Since the whole fraction is raised to the negative 1 power, we need to take a reciprocal of the fraction. Therefore,
$(\frac{7}{12})^{-1}=\frac{7^{-1}}{12^{-1}}=\frac{12}{7}$
