## Elementary Algebra

$\frac{12}{7}$
First, we simplify the expression within the parenthesis: $(\frac{1}{3}+\frac{1}{4})^{-1}$ =$(\frac{1(4)+1(3)}{12})^{-1}$ =$(\frac{4+3}{12})^{-1}$ =$(\frac{7}{12})^{-1}$ Since the whole fraction is raised to the negative 1 power, we need to take a reciprocal of the fraction. Therefore, $(\frac{7}{12})^{-1}=\frac{7^{-1}}{12^{-1}}=\frac{12}{7}$