Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set - Page 324: 53



Work Step by Step

First, we factor the expression by using the trinomial rules of factoring. Then, we equate the resultant factors to zero. $6t^{2}+19t-7=0$ $6t^{2}+21t-2t-7=0$ $3t(2t+7)-1(2t+7)=0$ $(2t+7)(3t-1)=0$ $(2t+7)=0$ and $(3t-1)=0$ $2t=-7$ and $3t=1$ $t=-\frac{7}{2}$ and $t=\frac{1}{3}$ Therefore, the solution set is {$-\frac{7}{2},\frac{1}{3}$}.
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