Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set - Page 324: 46



Work Step by Step

First, we will cross multiply the two sides of the equation to simplify it, and then we will solve the resultant equation: $\frac{3n-1}{4}=\frac{5n+2}{7}$ $7(3n-1)=4(5n+2)$ $21n-7=20n+8$ $21n-20n=8+7$ $n=15$ Therefore, the solution set is {$15$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.