## Elementary Algebra

{$15$}
First, we will cross multiply the two sides of the equation to simplify it, and then we will solve the resultant equation: $\frac{3n-1}{4}=\frac{5n+2}{7}$ $7(3n-1)=4(5n+2)$ $21n-7=20n+8$ $21n-20n=8+7$ $n=15$ Therefore, the solution set is {$15$}.