Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set: 46

Answer

{$15$}

Work Step by Step

First, we will cross multiply the two sides of the equation to simplify it, and then we will solve the resultant equation: $\frac{3n-1}{4}=\frac{5n+2}{7}$ $7(3n-1)=4(5n+2)$ $21n-7=20n+8$ $21n-20n=8+7$ $n=15$ Therefore, the solution set is {$15$}.
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