#### Answer

$\frac{9}{4}$

#### Work Step by Step

Recall the rule: $x^{-n}=\frac{1}{x^{n}}$
We first rearrange the expression into a form that doesn't contain any negative exponents, and then we solve the expression.
$(\frac{2}{3})^{-2}=\frac{2^{-2}}{3^{-2}}=\frac{3^{2}}{2^
{2}}=\frac{9}{4}$