Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - Chapters 1-7 Cumulative Review Problem Set: 15

Answer

$\frac{4}{25}$

Work Step by Step

We remove the negative sign in the exponent of the denominator by putting it in the numerator. Then, we raise each term in the expression to the power of 2 and simplify: $\frac{1}{(\frac{2}{5})^{-2}}$ =$(\frac{2}{5})^{2}$ =$(\frac{2^{2}}{5^{2}})$ =$\frac{4}{25}$
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