Elementary Algebra

$2x(x+6)(x-9)$
Since $2x$ is common to every term of the expression, we first factor out $2x$: =$2x^{3}-6x^{2}-108x$ =$2x(x^{2}-3x-54)$ Now, we find out that the equation in the parenthesis represents a trinomial which can be factorized by using the rules of factoring trinomials: =$2x(x^{2}-3x-54)$ =$2x(x^{2}+6x-9x-54)$ =$2x[x(x+6)-9(x+6)]$ =$2x[(x+6)(x-9)]$ =$2x(x+6)(x-9)$